Labels:text | screenshot | font | document OCR: c. An Earth-based computer monitoring the coordinates of Jupiter in Paysager's reference frame recorded Jupiter at (2.03, - 2.81, 0.336) (in units equivalent to 10"km) at one point. If Paysager had performed a yaw rotation of 28" just prior to this reading, what were Jupiter's coordinates in the spacecraft coordinate system? Solution: Using (x' ,y' ,z') for the spacecraft coordinate system: X' = x cos 28" + y sin 280 = 2.03 cos 280 - 2.81 sin 280= 0.473 y' = - x sin 28" + y cos 280 = - 2.03 sin 280 - 2.81 cos 280 = - 3.43 z' = z = 0.336 So the coordinates were (0.473, - 3.43, 0.336) in these units. We next calculate the length of some of the latitude circles on Earth.
